{"id":18057,"date":"2024-04-27T00:30:53","date_gmt":"2024-04-27T00:30:53","guid":{"rendered":"https:\/\/soicau4047.minhngocxoso.com\/?p=18057"},"modified":"2024-04-27T00:30:53","modified_gmt":"2024-04-27T00:30:53","slug":"top-2-cach-danh-lo-xien-quay-de-trung-tu-cao-thu","status":"publish","type":"post","link":"https:\/\/bachthulo24h.com\/top-2-cach-danh-lo-xien-quay-de-trung-tu-cao-thu\/","title":{"rendered":"top 2 c\u00e1ch \u0111\u00e1nh l\u00f4 xi\u00ean quay d\u1ec5 tr\u00fang t\u1eeb cao th\u1ee7"},"content":{"rendered":"
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L\u00f4 xi\u00ean quay hi\u1ec7n \u0111ang l\u00e0 h\u00ecnh th\u1ee9c \u0111\u00e1nh l\u00f4 \u0111\u1ec1 \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng ph\u1ed5 bi\u1ebfn. C\u00e1ch t\u00ednh l\u00f4 xi\u00ean quay kh\u00f4ng h\u1ec1 \u0111\u01a1n gi\u1ea3n v\u00e0 c\u1ea7n t\u00ecm hi\u1ec3u chi ti\u1ebft. H\u00ecnh th\u1ee9c ch\u01a1i n\u00e0y \u0111em l\u1ea1i t\u1ef7 l\u1ec7 th\u1eafng kh\u00e1 cao v\u00e0 ng\u01b0\u1eddi ch\u01a1i s\u1ebd thu \u0111\u01b0\u1ee3c nhi\u1ec1u, \u0111\u1ed9 r\u1ee7i ro th\u1ea5p. C\u00f3 r\u1ea5t nhi\u1ec1u c\u00e1ch t\u00ednh v\u00e0 ng\u01b0\u1eddi ch\u01a1i c\u1ea7n l\u1ef1a ch\u1ecdn c\u00e1ch ph\u00f9 h\u1ee3p nh\u1ea5t. Ch\u00fang t\u00f4i s\u1ebd g\u1eedi t\u1edbi t\u1ef7 l\u1ec7 \u0103n c\u0169ng nh\u01b0 c\u00e1ch t\u00ednh l\u00f4 xi\u00ean quay cho anh em c\u00f3 \u0111\u01b0\u1ee3c th\u00f4ng tin \u0111\u1ea7y \u0111\u1ee7, ch\u00ednh x\u00e1c nh\u1ea5t.<\/p>\n\n\n\n
Tr\u01b0\u1edbc khi bi\u1ebft t\u00ednh to\u00e1n \u0111\u01b0\u1ee3c con s\u1ed1 th\u00ec ch\u00fang ta c\u1ea7n hi\u1ec3u thu\u1eadt ng\u1eef n\u00e0y ngh\u0129a l\u00e0 g\u00ec? \u0110\u1eb7c \u0111i\u1ec3m ch\u01a1i ra sao?<\/p>\n\n\n\n
L\u00f4 xi\u00ean quay \u0111\u01b0\u1ee3c ng\u01b0\u1eddi ch\u01a1i hi\u1ec3u l\u00e0 c\u00e1c c\u1eb7p xi\u00ean 2, 3, hay 4. Ch\u00fang \u0111\u01b0\u1ee3c t\u1ea1o ra t\u1eeb c\u00e1c l\u00f4 xi\u00ean \u0111\u01a1n l\u1ebb. Ng\u01b0\u1eddi ch\u01a1i s\u1eed d\u1ee5ng c\u00e1ch ch\u01a1i xi\u00ean quay n\u00e0y thay v\u00ec ng\u1ed3i li\u1ec7t k\u00ea c\u00e1c c\u1eb7p xi\u00ean d\u1ec5 b\u1ecb nh\u1ea7m l\u1eabn. <\/p>\n\n\n\n
V\u00ed d\u1ee5 :<\/strong><\/p>\n\n\n\n N\u1ebfu ch\u00fang ta s\u1eed d\u1ee5ng c\u00e1c c\u1eb7p xi\u00ean quay l\u00e0 90,91,92,93<\/strong> s\u1ebd ra c\u00e1c c\u1eb7p xi\u00ean nh\u01b0 sau:<\/p>\n\n\n\n Xi\u00ean 2: 90-91, 90-92, 90-93, 91-92, 91-93, 92-93<\/p> Xi\u00ean 3: 90-91-92, 90-91-93, 90-92-93, 91-92-93<\/p> Xi\u00ean 4: 90-91-92-93<\/p><\/blockquote>\n\n\n\n Khi ch\u01a1i l\u00f4 xi\u00ean quay th\u00ec b\u1ea1n c\u1ea7n th\u1ef1c hi\u1ec7n \u0111\u00e1nh \u00edt nh\u1ea5t l\u00e0 2 con l\u00f4 c\u00f9ng v\u1ec1 s\u1ebd \u0111\u01b0\u1ee3c x\u00e9t th\u01b0\u1eddng. N\u1ebfu nh\u01b0 c\u00e0ng xu\u1ea5t hi\u1ec7n nhi\u1ec1u s\u1ebd c\u00e0ng th\u1eafng h\u01a1n, ti\u1ec1n v\u1ed1n kh\u00f4ng nh\u1eefng ph\u1ea3i b\u1ecf ra th\u1ea5p m\u00e0 t\u1ef7 l\u1ec7 th\u01b0\u1edfng l\u1ea1i r\u1ea5t cao.<\/p>\n\n\n\n C\u00e1ch \u0111\u00e1nh r\u1ea5t \u0111\u01a1n gi\u1ea3n. Anh em c\u00f3 th\u1ec3 ch\u1ecdn 2 s\u1ed1 m\u00e0 m\u00ecnh c\u1ea3m th\u1ea5y d\u1ec5 tr\u00fang nh\u1ea5t. N\u1ebfu nh\u01b0 v\u1ec1 c\u1ea3 th\u00ec c\u00f3 ngh\u0129a l\u00e0 b\u1ea1n \u0111\u00e3 chi\u1ebfn th\u1eafng. Tuy nhi\u00ean, n\u1ebfu nh\u01b0 1 trong 2 con kh\u00f4ng v\u1ec1 t\u1ee9c l\u00e0 b\u1ea1n \u0111\u00e3 thua.<\/p>\n\n\n\n Ch\u1ecdn 3 s\u1ed1 \u0111\u1ec3 \u0111\u00e1nh, n\u1ebfu tr\u00fang 2 con s\u1ed1 l\u00e0 chi\u1ebfn th\u1eafng. Ch\u00fang ta c\u00f3 th\u1ec3 t\u00ednh to\u00e1n t\u1ec9 l\u1ec7 \u0103n nh\u01b0 sau: 21,5% x 21,5% x 21,5% = 0.0134 = 1.34%. V\u1edbi c\u00f4ng th\u1ee9c tr\u00ean, ng\u01b0\u1eddi chi\u1ebfn th\u1eafng s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c ti\u1ec1n l\u00f4 xi\u00ean quay h\u01a1n so v\u1edbi s\u1ed1 v\u1ed1n m\u00ecnh b\u1ecf ra l\u00e0 3 l\u1ea7n.<\/p>\n\n\n\n B\u1ea1n c\u00f3 th\u1ec3 t\u00ednh to\u00e1n b\u1eb1ng c\u00e1ch ch\u1ecdn ra 4 c\u1eb7p s\u1ed1 d\u1ec5 v\u1ec1. Sau \u0111\u00f3 \u0111\u00e1nh 11 c\u1eb7p xi\u00ean kh\u00e1c nhau c\u1ee7a lo\u1ea1i 2, 3 v\u00e0 4.<\/p>\n\n\n\n V\u1edbi 2 tr\u00ean 4 con tr\u00ean v\u1ec1 th\u00ec b\u1ea1n s\u1ebd h\u00f2a v\u1ed1n. C\u00f2n tr\u01b0\u1eddng h\u1ee3p 3 tr\u00ean 4 con v\u1ec1 th\u00ec b\u1ea1n \u0111\u00e3 \u0111\u00e1nh c\u00f3 l\u00e3i. B\u1ea1n c\u00f3 th\u1ec3 s\u1ebd \u0111\u01b0\u1ee3c \u0103n v\u1edbi t\u1ef7 l\u1ec7 c\u1ef1c cao so v\u1edbi ti\u1ec1n ban \u0111\u1ea7u b\u1ecf ra \u0111\u1ebfn 70 l\u1ea7n.<\/p>\n\n\n\n M\u1ed7i l\u1ed7 xi\u00ean kh\u00e1c nhau s\u1ebd t\u01b0\u01a1ng \u1ee9ng v\u1edbi m\u1ed9t c\u00e1ch t\u00ednh ri\u00eang. C\u1ee5 th\u1ec3 l\u00e0:<\/p>\n\n\n\n Ch\u00fang ta s\u1ebd l\u1ef1a 2 con s\u1ed1 kh\u00e1c nhau \u0111\u1ec3 c\u00f3 m\u1ed9t c\u1eb7p \u0111\u00e1nh. T\u1ef7 l\u1ec7 \u0103n theo h\u00ecnh th\u1ee9c 1\/10. L\u00f4 n\u00e0y ch\u1ec9 \u0111\u01b0\u1ee3c coi l\u00e0 tr\u00fang th\u01b0\u1edfng khi m\u00e0 2 con l\u00f4 ph\u1ea3i c\u00f9ng v\u1ec1 trong ng\u00e0y \u0111\u00e1nh.<\/p>\n\n\n\nC\u00e1ch t\u00ednh l\u00f4 xi\u00ean quay <\/strong><\/h2>\n\n\n\n
C\u00e1ch \u0111\u00e1nh xi\u00ean quay 2<\/strong><\/h3>\n\n\n\n
\u0110\u00e1nh l\u00f4 xi\u00ean quay 3 nh\u01b0 th\u1ebf n\u00e0o?<\/strong><\/h3>\n\n\n\n
H\u01b0\u1edbng d\u1eabn c\u00e1ch \u0111\u00e1nh l\u00f4 xi\u00ean quay 4<\/strong><\/h3>\n\n\n\n
C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean quay (c\u1eadp nh\u1eadt 2024)<\/strong><\/h2>\n\n\n\n
C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean quay 2<\/strong><\/h3>\n\n\n\n