{"id":18024,"date":"2024-04-10T11:07:33","date_gmt":"2024-04-10T11:07:33","guid":{"rendered":"https:\/\/soicau4047.minhngocxoso.com\/?p=18024"},"modified":"2024-04-10T11:07:33","modified_gmt":"2024-04-10T11:07:33","slug":"tong-trong-lo-de-la-gi-cac-bo-tong-lo-de-gom-co-nhung-con-nao","status":"publish","type":"post","link":"https:\/\/bachthulo24h.com\/tong-trong-lo-de-la-gi-cac-bo-tong-lo-de-gom-co-nhung-con-nao\/","title":{"rendered":"t\u1ed5ng trong l\u00f4 \u0111\u1ec1 l\u00e0 g\u00ec? c\u00e1c b\u1ed9 t\u1ed5ng l\u00f4 \u0111\u1ec1 g\u1ed3m c\u00f3 nh\u1eefng con n\u00e0o?"},"content":{"rendered":"\n
T\u1ed5ng \u0111\u1ec1 l\u00e0 g\u00ec, v\u00e0 b\u1ed9 t\u1ed5ng trong l\u00f4 \u0111\u1ec1 c\u00f3 nh\u1eefng con g\u00ec? Ch\u1eafc h\u1eb3n \u0111\u00f3 l\u00e0 th\u1eafc m\u1eafc c\u1ee7a r\u1ea5t nhi\u1ec1u anh em l\u00f4 \u0111\u1ec1 th\u1ee7. Vi\u1ec7c ng\u01b0\u1eddi ch\u01a1i ghi nh\u1edb v\u00e0 n\u1eafm r\u00f5 \u0111\u01b0\u1ee3c c\u00e1c s\u1ed1 trong t\u1eebng b\u1ed9 t\u1ed5ng \u0111\u1ec1 l\u00e0 r\u1ea5t c\u1ea7n thi\u1ebft, \u0111i\u1ec1u \u0111\u00f3 g\u00f3p ph\u1ea7n gi\u00fap anh em soi c\u1ea7u v\u00e0 d\u1ef1 \u0111o\u00e1n \u0111\u01b0\u1ee3c nh\u1eefng con l\u00f4 s\u1ed1 \u0111\u1ec1 may m\u1eafn d\u1ec5 d\u00e0ng h\u01a1n r\u1ea5t nhi\u1ec1u. B\u00ean c\u1ea1nh \u0111\u00f3, n\u00f3 c\u00f2n gi\u00fap cho anh em n\u1eafm \u0111\u01b0\u1ee3c ph\u1ea7n th\u1eafng cao h\u01a1n trong khi \u0111\u00e1nh l\u00f4 \u0111\u1ec1 truy\u1ec1n th\u1ed1ng.<\/p>\n\n\n\n
Ch\u00ednh v\u00ec th\u1ebf, vi\u1ec7c n\u1eafm r\u00f5 v\u1ec1 c\u00e1c d\u00e0n \u0111\u1ec1 t\u1ed5ng trong l\u00f4 \u0111\u1ec1 r\u1ea5t quan tr\u1ecdng khi anh em ti\u1ebfn h\u00e0nh ch\u1ed1t s\u1ed1. H\u00e3y c\u00f9ng m\u1edbi nh\u1ea5t t\u00ecm hi\u1ec3u ngay t\u1ea1i b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ec3 c\u00f3 th\u1ec3 hi\u1ec3u r\u00f5 h\u01a1n v\u1ec1 kh\u00e1i ni\u1ec7m t\u1ed5ng trong l\u00f4 \u0111\u1ec1 n\u00e0y.<\/p>\n\n\n\n
T\u1ed5ng \u0111\u1ec1 l\u00e0 m\u1ed9t b\u1ed9 s\u1ed1 trong nhi\u1ec1u b\u1ed9 s\u1ed1 trong l\u00f4 \u0111\u1ec1. V\u00ec th\u1ebf tr\u01b0\u1edbc h\u1ebft ch\u00fang ta s\u1ebd t\u00ecm hi\u1ec3u b\u1ed9 s\u1ed1 trong l\u00f4 \u0111\u1ec1 l\u00e0 g\u00ec.<\/p>\n\n\n\n
V\u1eady \u201cb\u1ed9 s\u1ed1 trong l\u00f4 \u0111\u1ec1\u201d l\u00e0 t\u1eadp h\u1ee3p nh\u1eefng con s\u1ed1 c\u00f3 c\u00f9ng \u0111\u1eb7c \u0111i\u1ec3m.<\/p>\n\n\n\n
V\u00ed d\u1ee5:<\/p>\n\n\n\n
B\u1ed9 s\u1ed1 k\u00e9p b\u1eb1ng l\u00e0 b\u1ed9 s\u1ed1 c\u00f3 2 s\u1ed1 gi\u1ed1ng nhau, bao g\u1ed3m c\u00e1c s\u1ed1 nh\u01b0 sau: 00, 11, 22, 33, 44, 55, 66, 77, 88, 99.<\/p>\n\n\n\n
B\u1ed9 s\u1ed1 k\u00e9p l\u1ec7ch l\u00e0 b\u1ed9 s\u1ed1 c\u00f3 s\u1ed1 n\u00e0y l\u00e0 b\u00f3ng c\u1ee7a s\u1ed1 kia, b\u1ed9 s\u1ed1 n\u00e0y g\u1ed3m nh\u1eefng s\u1ed1 sau: 05, 50, 16, 61, 27, 72, 38, 83, 49, 94<\/p>\n\n\n\n
C\u00f3 r\u1ea5t nhi\u1ec1u c\u00e1c b\u1ed9 s\u1ed1 trong l\u00f4 \u0111\u1ec1. Nh\u1eefng b\u1ed9 s\u1ed1 n\u00e0y \u00e1p d\u1ee5ng cho c\u1ea3 ghi l\u00f4 \u0111\u1ec1 truy\u1ec1n th\u1ed1ng v\u00e0 \u0111\u00e1nh l\u00f4 \u0111\u1ec1 online. Tuy nhi\u00ean trong b\u00e0i vi\u1ebft n\u00e0y ch\u00fang t\u00f4i s\u1ebd ch\u1ec9 n\u00f3i v\u1ec1 b\u1ed9 s\u1ed1 T\u1ed5ng m\u00e0 th\u00f4i.<\/p>\n\n\n\n
T\u1ed5ng \u0111\u1ec1 l\u00e0 t\u1eadp h\u1ee3p c\u00e1c con s\u1ed1 m\u00e0 khi ta c\u1ed9ng 2 ch\u1eef s\u1ed1 c\u1ee7a c\u00e1c s\u1ed1 th\u00ec \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 b\u1eb1ng nhau. K\u1ebft qu\u1ea3 t\u1ed5ng 2 ch\u1eef s\u1ed1 n\u00e0y \u0111\u01b0\u1ee3c t\u00ednh theo c\u00e1ch t\u00ednh c\u1ee7a b\u00e0i 3 c\u00e2y. \u0110\u1ec3 h\u00ecnh dung r\u00f5 h\u01a1n, b\u1ea1n \u0111\u1ecdc xem v\u00ed d\u1ee5 tr\u1ef1c ti\u1ebfp sau \u0111\u00e2y:<\/p>\n\n\n\n
– S\u1ed1 18 n\u1eb1m trong t\u1ed5ng 9 v\u00ec c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1: 1 + 8 = 9<\/p>\n\n\n\n
T\u01b0\u01a1ng t\u1ef1: s\u1ed1 27 c\u0169ng n\u1eb1m trong t\u1ed5ng 9 v\u00ec c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 l\u00e0 2 + 7 = 9<\/p>\n\n\n\n
– S\u1ed1 73 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 l\u00e0 7 + 3 = 10. Tuy nhi\u00ean t\u00ednh theo c\u00e1ch t\u00ednh c\u1ee7a b\u00e0i 3 c\u00e2y n\u00ean 7 + 3 = 10 t\u00ednh 0 \u0111i\u1ec3m. V\u1eady s\u1ed1 73 n\u1eb1m trong t\u1ed5ng 0.<\/p>\n\n\n\n
T\u01b0\u01a1ng t\u1ef1: s\u1ed1 55 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 l\u00e0 5 + 5 = 10 => S\u1ed1 55 c\u0169ng n\u1eb1m trong t\u1ed5ng 0.<\/p>\n\n\n\n
R\u1ea5t d\u1ec5 hi\u1ec3u ph\u1ea3i kh\u00f4ng c\u00e1c b\u1ea1n. V\u1eady t\u1ed5ng c\u1ed9ng c\u00f3 bao nhi\u00eau b\u1ed9 s\u1ed1, ta c\u00f9ng t\u00ecm hi\u1ec3u \u1edf ph\u1ea7n ti\u1ebfp theo.<\/p>\n\n\n\n
Anh em n\u00ean ch\u00fa \u00fd r\u1eb1ng t\u1ed5ng trong l\u00f4 \u0111\u1ec1 ch\u1ec9 \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng v\u1edbi s\u1ed1 \u0111\u1ec1 \/ gi\u1ea3i \u0111\u1eb7c bi\u1ec7t.<\/p>\n\n\n\n
\u1ede ph\u1ea7n n\u00e0y ch\u00fang t\u00f4i s\u1ebd t\u1ed5ng h\u1ee3p l\u1ea1i chi ti\u1ebft v\u00e0 ch\u00ednh x\u00e1c c\u00e1c b\u1ed9 s\u1ed1 trong t\u1eebng t\u1ed5ng \u0111\u1ec1 \u0111\u1ec3 anh em c\u00f3 th\u1ec3 n\u1eafm r\u00f5. Do t\u1ed5ng 2 con s\u1ed1 c\u1ee7a c\u00e1c s\u1ed1 trong t\u1ed5ng \u0111\u1ec1 \u0111\u01b0\u1ee3c t\u00ednh theo c\u00e1ch t\u00ednh c\u1ee7a b\u00e0i 3 c\u00e2y (b\u00e0i c\u00e0o) v\u00ec v\u1eady t\u1ed5ng l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc,mi\u1ec1n Nam, hay mi\u1ec1n Trung \u0111\u1ec1u c\u00f3 10 b\u1ed9 t\u1ed5ng. C\u00e1c b\u1ed9 t\u1ed5ng \u0111\u1ec1 s\u1ebd \u0111\u01b0\u1ee3c li\u1ec7t k\u00ea l\u1ea7n l\u01b0\u1ee3t t\u1eeb \u0111\u1ec1 t\u1ed5ng 0, \u0111\u1ec1 t\u1ed5ng 1, \u0111\u1ec1 t\u1ed5ng 2, \u0111\u1ec1 t\u1ed5ng 3, \u0111\u1ec1 t\u1ed5ng 4, \u0111\u1ec1 t\u1ed5ng 5, \u0111\u1ec1 t\u1ed5ng 6, \u0111\u1ec1 t\u1ed5ng 7, \u0111\u1ec1 t\u1ed5ng 8, \u0111\u1ec1 t\u1ed5ng 9.<\/p>\n\n\n\n